Posted on

Descritpion

Submission

class Solution {
public:
    bool isIsomorphic(string s, string t) {
        unordered_map<char, char> m1;
        unordered_map<char, char> m2;

        int n = s.size();
        for(int i = 0; i < n; ++i) {
            if(m1.find(s[i]) == m1.end()) {
                m1[s[i]] = t[i];
            } else {
                if(m1[s[i]] != t[i]) return false;
            }

            if(m2.find(t[i]) == m2.end()) {
                m2[t[i]] = s[i];
            } else {
                if(m2[t[i]] != s[i]) return false;
            }
        }
        return true;
    }
};

Leave a Reply

Your email address will not be published. Required fields are marked *